【C#】Deep copy of objects

If you learned C++ carefully, you must have known something about the copy of object.

For example, I defined a class called \(ABC\)，and two variable \(x\) and \(y\) are \(ABC\)s.

Like this:

 class ABC{

     public:

         int a,b;

 };

 int main(){

     ABC x,y;

     x.a=;x.b=;

     y=x;

     y.a=;

     return ;

 };

Certainly,\( y.a==3 , y.b==2 \), and, what's more, \( x.a==1,x.b==2 \).

So in fact,a deep copy was made in the line 8.

But in C#,this can be different, if you operate like this, \( x.a==3,x.b==2 \) would be the result, for x and y is the same variable.

So how can we make a deep copy? Do not worry,we can serialize it and then turn it back!

(Remember : Don't forget to put a \([Serializable]\) before the defination of the object!!!)

Enjoy it:(Line 31-35)

 using System;

 using System.Collections.Generic;

 using System.Linq;

 using System.Text;

 using System.Threading.Tasks;

 using System.IO;

 using System.Runtime;

 using System.Runtime.Serialization.Formatters.Binary;

 using System.Runtime.Serialization;

 using System.Runtime.InteropServices;

 namespace DataTrans

 {

     public class Switcher

     {

         public byte[] Object2Bytes(object obj)

         {

             IFormatter fmt = new BinaryFormatter();

             MemoryStream ms = new MemoryStream();

             fmt.Serialize(ms, obj);

             return ms.GetBuffer();

         }

         public object Bytes2Object(byte[] bt)

         {

             IFormatter fmt = new BinaryFormatter();

             MemoryStream ms = new MemoryStream(bt);

             return (object)fmt.Deserialize(ms);

         }

         public T DeepCopy<T>(T __dt)

         {

             byte[] bt = Object2Bytes(__dt);  //serialize

             return (T)Bytes2Object(bt);  //deserialize

         }

         public Switcher()

         {

         }

     }

 }

巴特西

【C#】Deep copy of objects

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