HDU 5651xiaoxin juju needs help
2024-09-29 16:48:23
xiaoxin juju needs help
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 1310 Accepted Submission(s): 378
Problem Description
As we all known, xiaoxin is a brilliant coder. He knew **palindromic** strings when he was only a six grade student at elementry school.
This summer he was working at Tencent as an intern. One day his leader came to ask xiaoxin for help. His leader gave him a string and he wanted xiaoxin to generate palindromic strings for him. Once xiaoxin generates a different palindromic string, his leader will give him a watermelon candy. The problem is how many candies xiaoxin's leader needs to buy?
Input
This problem has multi test cases. First line contains a single integer T(T≤20) which represents the number of test cases.
For each test case, there is a single line containing a string S(1≤length(S)≤1,000).
For each test case, there is a single line containing a string S(1≤length(S)≤1,000).
Output
For each test case, print an integer which is the number of watermelon candies xiaoxin's leader needs to buy after mod 1,000,000,007.
Sample Input
3
aa
aabb
a
Sample Output
1
2
1
排列组合问题。C[n][m]用dp求一下。
然后对于aabababbcc这组样例 我们取1/2进行考虑,aabbc. 答案就是c(5,2)*c(3,2)*c(1,1)
/* ***********************************************
Author :
Created Time :2016/3/30 15:28:22
File Name :hdu5651.cpp
************************************************ */
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <stdio.h>
#include <algorithm>
#include <vector>
#include <queue>
#include <set>
#include <map>
#include <string>
#include <math.h>
#include <stdlib.h>
#include <iomanip>
#include <list>
#include <deque>
#include <stack>
#define ull unsigned long long
#define ll long long
#define mod 1000000007
#define INF 0x3f3f3f3f
#define maxn 10010
#define cle(a) memset(a,0,sizeof(a))
const ull inf = 1LL << ;
const double eps=1e-;
using namespace std;
priority_queue<int,vector<int>,greater<int> >pq;
struct Node{
int x,y;
};
struct cmp{
bool operator()(Node a,Node b){
if(a.x==b.x) return a.y> b.y;
return a.x>b.x;
}
}; bool cmp(int a,int b){
return a>b;
}
char s[maxn];
int cnt[];
int c[][];
void init(){
memset(c,,sizeof c);
for(int i=;i<;i++){
c[i][]=i;c[i][]=;
}
for(int i=;i<=;i++){
for(int j=;j<=i;j++){
c[i][j]=(c[i-][j-]+c[i-][j])%mod;
}
}
}
void solve(int n){
n/=;
ll ans=,sum=n;
for(int i=;i<;i++){
ans*=c[n][cnt[i]/];
ans%=mod;
n-=cnt[i]/;
}
cout<<ans<<endl;
}
int main()
{
#ifndef ONLINE_JUDGE
freopen("in.txt","r",stdin);
#endif
//freopen("out.txt","w",stdout);
int t;
cin>>t;
init();
while(t--){
scanf("%s",&s);
cle(cnt);
int n=strlen(s);
for(int i=;i<n;i++){
cnt[int(s[i]-'a')]++;
}
int mark=;
for(int i=;i<;i++){
if(cnt[i]&){
mark++;
}
}
if(n%==){
if(mark>){
printf("%d\n",);continue;
}
solve(n);
}
else{
if(mark==){
solve(n);
}
else{
printf("%d\n",);
}
} }
return ;
}
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