[TypeScript] Simplify asynchronous callback functions using async/await
2024-08-31 21:31:00
Learn how to write a promise based delay function and then use it in async await to see how much it simplifies code over setTimeout.
Lets say you want to call a function after 1s, 2s, 3s. You can use setTimeout, or you can wrap it up into a simple delay function that works with async/await
We want to conver this code
const run = (cb) => {
setTimeout(() => {
cb('1s');
setTimeout(() => {
cb('2s');
setTimeout(() => {
cb('3s');
}, 1000);
}, 1000);
}, 1000);
}
to:
const delay = (ms) => new Promise(res => setTimeout(res, ms));
const runAsync = async (cb) => {
await delay(1000);
cb('1s');
await delay(1000);
cb('2s');
await delay(1000);
cb('3s');
}
runAsync((time) => console.log(time));
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