Problem Description

Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.

 

Input

The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);

 

Output

For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.

 

Sample Input

 

Sample Output

 #include<bits/stdc++.h>

 using namespace std;

 double f(double x)

 {

     return (*x*x*x*x+*x*x*x+*x*x+*x+);

  }

 int main()

 {

     int t;

     while(~scanf("%d",&t))

     {

         while(t--)

         {

             double y;

             scanf("%lf",&y);

             if(f()>y||f()<y)

             {

                 printf("No solution!\n");

                 continue;

             }

             double l,r;

             l=0.0;r=100.0;

             double mid=50.0;

             while(fabs(f(mid)-y)>1e-)

             {

                 if(f(mid)>y)

                 {

                     r=mid;

                     mid=(l+r)/2.0;

                 }

                 else

                 {

                     l=mid;

                     mid=(l+r)/2.0;

                 }

             }

             printf("%.4lf\n",mid);

         }

     }

     return ;

 }