UVA 11388-GCD LCM(数学)
I I U C O N L I N E |
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Problem D: GCD LCM |
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Input: standard input |
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The GCD of two positive integers is the largest integer that divides both the integers without any remainder. The LCM of two positive integers is the smallest positive integer that is divisible by both the integers. A positive integer can be the GCD of many |
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Input |
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The first line of input will consist of a positive integer T. T denotes the number of cases. Each of the next T lines will contain two positive integer, G and L. |
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Output |
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For each case of input, there will be one line of output. It will contain two positive integers a and b, a ≤ b, which has a GCD of G and LCM of L. In case there is more |
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Constraints |
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- T ≤ 100 - Both G and L will be less than 231. |
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Sample Input |
Output for Sample Input |
2 1 2 3 4 |
1 2 -1 |
Problem setter: Shamim Hafiz 题意 :给出两个数G,L,问是否存在一对数a,b。使得gcd(a,b)==G,lcm(a,b)==L; 能够这么想:当gcd(G,L)==G(a),lcm(G,L)==L(b)时。此时G==a,L==b,满足上述条件。否则不成立。
#include <cstdio> |
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