47. 全排列 II

1、C

/**
* Return an array of arrays of size *returnSize.
* The sizes of the arrays are returned as *returnColumnSizes array.
* Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().
*/
void back(int* nums, int numsSize, int* returnSize, int** returnColumnSizes,int *path,int *pathSize,int **result,int *visited){
if(numsSize==*pathSize){
result[*returnSize] = (int *)malloc(sizeof(int)*numsSize);
memcpy(result[*returnSize],path,sizeof(int)*numsSize);
(*returnColumnSizes)[*returnSize] = numsSize;
(*returnSize)++;
return;
}
for(int i=0;i<numsSize;i++){
if(visited[i]==1||(i>0&&nums[i-1]==nums[i]&&visited[i-1]==0)){
continue;
}
path[*pathSize] = nums[i];
visited[i] = 1;
(*pathSize)++;
back(nums,numsSize,returnSize,returnColumnSizes,path,pathSize,result,visited);
visited[i] = 0;
(*pathSize)--;
}
}
void QuickSort1(int* a, int left, int right)
{
if (left >= right)
{
return;
} int begin = left, end = right;
//三数取中
//int midIndex = GetThreeMid(a,begin,end);
//Swap(&a[begin],&a[midIndex]);
int pivot = begin;
int key = a[begin]; while (begin < end)
{
//右边找小的,如果不是小于key,继续
while (begin < end && a[end] >= key)
{
end--;
}
//找到比key小的,把它放在坑里,换新坑
a[pivot] = a[end];
pivot = end;
//左边找大的,如果不是大于key,继续
while (begin < end && a[begin] <= key)
{
begin++;
}
//找到比key大的,把它放在坑里,换新坑
a[pivot] = a[begin];
pivot = begin;
} a[pivot] = key;//bengin 与 end 相遇,相遇的位置一定是一个坑
QuickSort1(a, left, pivot - 1);
QuickSort1(a, pivot + 1, right);
}
int** permuteUnique(int* nums, int numsSize, int* returnSize, int** returnColumnSizes){
QuickSort1(nums,0,numsSize-1);
*returnSize = 0;
*returnColumnSizes = (int *)malloc(sizeof(int)*100001);
int *path = (int *)malloc(sizeof(int)*numsSize);
int **result = (int **)malloc(sizeof(int *)*100001);
int *visited = (int *)calloc(numsSize,sizeof(int));
int *pathSize = (int *)calloc(1,sizeof(int));
back(nums,numsSize,returnSize,returnColumnSizes,path,pathSize,result,visited);
return result; }

2、C++

class Solution {
public:
vector<int> path;
vector<vector<int>> result;
void back(vector<int>& nums,vector<bool>& visited){
if(path.size()==nums.size()){
result.push_back(path);
return;
}
for(int i=0;i<nums.size();i++){
if(visited[i]||(i>0 && nums[i-1]==nums[i]&&visited[i-1]==false)){
continue;
}
path.push_back(nums[i]);
visited[i] = true;
back(nums,visited);
visited[i] = false;
path.pop_back();
}
}
vector<vector<int>> permuteUnique(vector<int>& nums) {
sort(nums.begin(),nums.end());
vector<bool> visited(nums.size(),false);
back(nums,visited);
return result;
}
};

3、JAVA

class Solution {
List<List<Integer>> result = new ArrayList<>();
LinkedList<Integer> path = new LinkedList<>();
void back(int[] nums,boolean[] visited){
if(nums.length == path.size()){
result.add(new ArrayList<>(path));
return;
}
for(int i=0;i<nums.length;i++){
if(visited[i]){continue;}
if(i>0&&nums[i-1]==nums[i]&&visited[i]==false&&visited[i-1]==false){
continue;
}
visited[i] = true;
path.add(nums[i]);
back(nums,visited);
path.removeLast();
visited[i] = false;
}
}
public List<List<Integer>> permuteUnique(int[] nums) {
Arrays.sort(nums);
boolean visited[] = new boolean[nums.length];
Arrays.fill(visited,false);
back(nums,visited);
return result;
}
}

4、Python

class Solution(object):
def __init__(self):
self.path = []
self.result = []
def back(self,nums,visited):
if len(nums)==len(self.path):
self.result.append(self.path[:])
return
for i in range(len(nums)):
if visited[i]==True:
continue
if i>0 and nums[i-1]==nums[i] and visited[i-1]==False:
continue
visited[i]=True
self.path.append(nums[i])
self.back(nums,visited)
self.path.pop()
visited[i]=False def permuteUnique(self, nums):
"""
:type nums: List[int]
:rtype: List[List[int]]
"""
nums.sort()
visited = [False]*len(nums)
self.back(nums,visited)
return self.result

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