Area
Time Limit: 1000MS Memory Limit: 10000K
Total Submissions: 4373 Accepted: 1983

Description

Being well known for its highly innovative products, Merck would definitely be a good target for industrial espionage. To protect its brand-new research and development facility the company has installed the latest system of surveillance robots patrolling the area. These robots move along the walls of the facility and report suspicious observations to the central security office. The only flaw in the system a competitor抯 agent could find is the fact that the robots radio their movements unencrypted. Not being able to find out more, the agent wants to use that information to calculate the exact size of the area occupied by the new facility. It is public knowledge that all the corners of the building are situated on a rectangular grid and that only straight walls are used. Figure 1 shows the course of a robot around an example area.

 
Figure 1: Example area. 
You are hired to write a program that calculates the area occupied by the new facility from the movements of a robot along its walls. You can assume that this area is a polygon with corners on a rectangular grid. However, your boss insists that you use a formula he is so proud to have found somewhere. The formula relates the number I of grid points inside the polygon, the number E of grid points on the edges, and the total area A of the polygon. Unfortunately, you have lost the sheet on which he had written down that simple formula for you, so your first task is to find the formula yourself. 

Input

The first line contains the number of scenarios. 
For each scenario, you are given the number m, 3 <= m < 100, of movements of the robot in the first line. The following m lines contain pairs 揹x dy�of integers, separated by a single blank, satisfying .-100 <= dx, dy <= 100 and (dx, dy) != (0, 0). Such a pair means that the robot moves on to a grid point dx units to the right and dy units upwards on the grid (with respect to the current position). You can assume that the curve along which the robot moves is closed and that it does not intersect or even touch itself except for the start and end points. The robot moves anti-clockwise around the building, so the area to be calculated lies to the left of the curve. It is known in advance that the whole polygon would fit into a square on the grid with a side length of 100 units. 

Output

The output for every scenario begins with a line containing 揝cenario #i:� where i is the number of the scenario starting at 1. Then print a single line containing I, E, and A, the area A rounded to one digit after the decimal point. Separate the three numbers by two single blanks. Terminate the output for the scenario with a blank line.

Sample Input

2
4
1 0
0 1
-1 0
0 -1
7
5 0
1 3
-2 2
-1 0
0 -3
-3 1
0 -3

Sample Output

Scenario #1:
0 4 1.0 Scenario #2:
12 16 19.0 给一个n边形,求出其内部整点数I,边界上整点数E以及其面积s;
根据pick定理有s = I+E/2-1;所以先求出多边形面积和E,I就可以得出了;

 #include<stdio.h>
#include<istream>
#include<algorithm>
#include<math.h>
using namespace std; const int N = ;
struct Point//定义点
{
double x,y;
Point() {}
Point (double a,double b):x(a),y(b) {}
} p[N]; double det(const Point &a,const Point &b)
{
return(a.x*b.y-a.y*b.x);
}//计算两个向量的叉积; int gcd(int a, int b)
{
return b == ?a:gcd(b,a%b);
} int main()
{
int test, item;
scanf("%d",&test);
for(item = ; item <= test; item++)
{
int n;
scanf("%d",&n);
int x,y,num = ;
p[].x = ;
p[].y= ;
for(int i = ; i <= n; i++)
{
scanf("%d %d",&x,&y); num += gcd(abs(x),abs(y));//多边形边界上整点数; p[i].x = p[i-].x + x;
p[i].y = p[i-].y + y;
} double sum=;
for(int i=; i<n; i++)
sum+=det(p[i],p[i+]); printf("Scenario #%d:\n",item);
printf("%d %d %.1lf\n",int(sum/2.0)+-(num/),num,sum/);
printf("\n");
}
}
 

最新文章

  1. Sharepoint学习笔记—习题系列--70-576习题解析 -(Q1-Q3)
  2. VIJOS1476旅游规划[树形DP 树的直径]
  3. [CoreOS 转载] CoreOS实践指南(七):Docker容器管理服务
  4. mysql 管理、备份、还原及查询的图形化gui工具
  5. js、javascript正则表达式验证身份证号码
  6. cf498C Array and Operations
  7. 在Build时使用NuGet自动下载缺失的包
  8. 拖动条(SeekBar)的功能和用法
  9. Mysql 删除重复记录,只保留最小的一条
  10. 关于HTTP协议,这一篇就够了
  11. 以springMVC为例获取上传视频文件时长
  12. mycat 使用
  13. 01day
  14. Weighted Quick Union with Path Compression (WQUPC)
  15. PE文件 01 导入表
  16. 使用 jfreechart 生成 曲线、柱状图、饼状图、分布图 展示到JSP
  17. Node.js Streams:你需要知道的一切
  18. LARTC
  19. [C#.NET] X509 數位電子簽章
  20. CentOS 7.0 yum安装Apache、PHP和MySQL

热门文章

  1. navigation的pushViewController卡顿问题
  2. docker入门(一)
  3. 关于javascript dom扩展:Selector API
  4. spring验证事务的代码,用到了mockito
  5. Android图表引擎AChartEngine之折线图使用
  6. 关于mssql数据库锁和事务隔离级别
  7. bash: ./configure: 权限不够 怎么办?
  8. Index Full Scan vs Index Fast Full Scan-1103
  9. ZOJ2112 Dynamic Rankings 动态区间第K最值 平方分割
  10. JS 打字机效果