jquery ajax return jsonresult pattern

//javascript
var queryParams = {
"userId": userId,
"factoryId": factoryId
};

$.ajax({
    type: "POST", //默认是GET
    url: "/Home/SubmitToProcessed",
    data: queryParams,
    async: false, //异步
    cache: false, //不加载缓存
    dataType: "json",
    success: function (data) {

   //return single entity
   if (data.result) {
        $("#contentBefore").hide();
        $("#contentAfter").show();
   }
   else {
        $.messager.alert("操作失败", data.message);
   }

//return entity list
   foreach( var item in list)
   {
        item.id,
        item.categoryName,
   }
    },
    error: function (xmlHttpRequest, textStatus, errorThrown) {
   $.messager.alert("操作失败", "操作失败");
    }
});

//c# action
[HttpPost]
public JsonResult SubmitToProcessed(FormCollection collection)
{
   boolean rlt = true //......call function;
   return Json(new { result = rlt, message = (rlt == false ? "操作失败":"") }, JsonRequestBehavior.AllowGet);

List<user> userlst = .....
return Json(userlst, JsonRequestBehavior.AllowGet);
}

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jquery ajax return jsonresult pattern

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