Java小案例-(逃离迷宫)
2024-09-02 04:57:00
Java小案例-(逃离迷宫)
一,迷宫需求描述:
1,用户输入迷宫图(限制方形):字母1位墙,0为通,e为出口,m为入口,*为已访问的位置,用外围1围住迷宫
2,运行轨迹右,左,下,上
3,判断该迷宫是否能从入口走到出口,并将搜索过程输出
二,迷宫实现:
1,迷宫元素类MazeCell:
package smalldemo.maze; class MazeCell {
public int x,y;
public MazeCell(){
}
public MazeCell(int x,int y){
this.x=x;
this.y=y;
}
public boolean equals(MazeCell cell){
return x==cell.x && y==cell.y;
}
}
2,迷宫搜索类MazeUtils:
package smalldemo.maze; import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.io.PrintStream;
import java.util.Stack;
class MazeUtils {
private int rows,columns;
private MazeCell currentCell,exitCell=new MazeCell(),entryCell=new MazeCell();
private final char wall='1',passage='0',visited='*',entryMarker='m',exitMarker='e';
private char[][] stores;
private Stack<MazeCell> mazePath=new Stack<MazeCell>();
MazeUtils(){
int row=0,column=0; InputStreamReader in=new InputStreamReader(System.in);
BufferedReader buf=new BufferedReader(in);
Stack<String> mazeRows=new Stack<String>();
System.out.println("Enter a rectangular maze using the following"+
"characters\nm -entry\ne -exit\n1 - wall \n0 - passage\n"+"Enter one line at one time:" +
"end with Ctrl- D:");
try {
String str=buf.readLine();
while(str !=null) {
row += 1;
columns = str.length();
str = "1" + str + "1";
mazeRows.push(str);
if (str.indexOf(entryMarker) != -1) {
entryCell.x = row;
entryCell.y = str.indexOf(entryMarker);
}
if (str.indexOf(exitMarker) != -1) {
exitCell.x = row;
exitCell.y = str.indexOf(exitMarker);
}
str = buf.readLine(); }
} catch (IOException e) {
e.printStackTrace();
}
rows=row;
stores=new char[rows+2][];
stores[0]=new char[columns+2];
for(;!mazeRows.empty();row --){
stores[row]=mazeRows.pop().toCharArray();
}
stores[rows+1]=new char[columns+2];
for(int i=0;i<columns+2;i+=1){
stores[0][i]=wall;
stores[rows+1][i]=wall;
}
}
private void display(PrintStream out){
for(int row =0;row <rows +1;row+=1){
out.println(stores[row]);
}
out.println();
}
private void pushUnvisited(int row,int col){
if(stores[row][col] ==passage || stores[row][col] == exitMarker){
mazePath.push(new MazeCell(row,col));
}
}
public void exitMaze(PrintStream out){
currentCell=entryCell;
out.println();
while (!currentCell.equals(exitCell)){
int x=currentCell.x;
int y=currentCell.y;
display(System.out);
stores[x][y]=visited;
pushUnvisited(x-1,y);
pushUnvisited(x+1,y);
pushUnvisited(x,y-1);
pushUnvisited(x,y+1);
if(mazePath.isEmpty()){
display(out);
out.println("Failure");
return;
}
else{
currentCell=mazePath.pop();
}
}
display(out);
out.println("Success!");
}
public static void main(String[] args){
new MazeUtils().exitMaze(System.out);
}
}
3,结果是:
Enter a rectangular maze using the followingcharacters
m -entry
e -exit
1 - wall
0 - passage
Enter one line at one time:end with Ctrl- D:
1101
000e
00m1
^D 111111
111011
1000e1
100m11 111111
111011
1000e1
100*11 111111
111011
1000e1
10**11 111111
111011
1000e1
1***11 111111
111011
1*00e1
1***11 111111
111011
1**0e1
1***11 111111
111011
1***e1
1***11 Success! Process finished with exit code 0
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