import re
import unicodedata s = "a00xoghasalexjkdfldhfjk"
v = s.find("alex")
print(v) k = ""
# 正则模糊匹配 # print(re.findall("alex", s))
# # .是通配符(除了换行之外)
# print(re.findall("a..x", s))
# # ^ (开头)和 $(结尾)
# print(re.findall("^a..x", s))
# print(re.findall("h..k$", s))
# # * (0-max) ;+(1,max) ; ? (0,1) 贪婪匹配
# b = "ccsrwrfdddddddddddkokosadkfod"
# print(re.findall("d*", b))
# print(re.findall("d+", b))
# print(re.findall("alex*", "asdhfale")) # 0-无穷大个
# print(re.findall("alex+", "asdhfale")) # 1-无穷大
# print(re.findall("alex?", "asdhfalex")) # 0-1个
# print(re.findall("alex?", "asdhfale")) # 0-1个
#
# # {}0-无穷大个 == * ; {1,} == + ; {6} 6次
# # {} 可以带贪婪匹配
# print(re.findall("alex{1,4}", "asdhfalexxx")) # 1-4个
# print(re.findall("alex{6}", "asdhfalexxx")) # 必须是6个
# # ? 惰性匹配
# print(re.findall("alex*?", "asdhfalexxx"))
# print(re.findall("alex+?", "asdhfalexxx"))
#
# # []字符集 中没有特殊符号(除了\-^)
# print(re.findall("www[oldboy baidu]", "wwwbaidu"))
# print(re.findall("x[ys]", "xyyszz"))
# print(re.findall("s[zby]a", "xyyszasya"))
# print(re.findall("s[zb,]a", "xyyszas,a"))
#
# print(re.findall("s[zb,]a", "xyyszas,a"))
# print(re.findall("s[zb*]a", "xyyscas,a"))
#
# # -之间
# print(re.findall("s[a-z]*", "sqaaaaerqwr"))
# print(re.findall("s[a-z]*", "sqaaaaerqwr9")) # [a-z] 之间
#
# print(re.findall("s[0-9]*", "s9qaaaaerqwr9")) # [a-z] 之间
# # ^非
# print(re.findall("s[^a-z]", "sqaaaaerqwr9")) # [a-z] 之间
# # \转义
# print(re.findall("\([^()]*\)", "12*(34*6+2-5*(2-1))"))
# print(re.findall("\([^()]+\)", "12*(34*6+2-5*(2-1))"))
#
# # \d 【0-9】的数值
# print(re.findall("\d+", "12*(34*6+2-5*(2-1))")) # [0-9]
# print(re.findall("\D+", "12*(34*6+2-5*(2-1))")) # [^0-9]
# print(re.findall("\s+", "hello world"), "ssss") # \t\n\r\f\v 任何空白符
# print(re.findall("\S+", "hello world")) # [^\t\n\r\f\v]
# print(re.findall("\w+", "hello world")) # [0-9a-zA-Z_]
# print(re.findall("\W", "hello world")) # [^0-9a-zA-Z_]
# print(re.findall("\b", "hello world")) # 空格,&,#
#
# print(re.findall(r"I\b", "hello I am world")) #
# print(re.findall("I\\b", "hello I am world")) #
# # print(re.findall("c\\\f", r"abcde\fgh"))
# # | 或
# print(re.findall("gh|f", "abcde|fgh"))
# # () 分组
# print(re.findall("(abf)*", r"abfabfabfh"))
#
# print(re.findall("(?P<name>\w+)", r"abfabfabfh"))
#
# # search 找到第一个就返回一个对象(需要用group取出),,findall找到所有满足的结果放入列表
#
# print(re.search("\d+","23414afdfasf324fa"))
# print(re.search("\d+","23414afdfasf324fa").group())
# # 分组命名
# print(re.search("(?P<name>[a-z]+)(?P<age>\d+)","23414alex324fa").group("name","age"))
#
# # match 成功返回对象,失败啥也不返回
# print(re.match("\d+", "24dsd143f"))
#
# # split 分割
# print(re.split(" ", "hello abc asf"))
# print(re.split("[ |]", "hello abc|asf"))
# print(re.split("[ab]", "hebllo abc|asf"))
# # ["he","llo abc|asf"]->["he",“llo ","bc|asf"]->
# # ["he","llo "," ","c|asf"]->["he","llo "," ","c|","sf"],
# print(re.split("[ab]", "abc"))
# # 替换
# print(re.sub("\d+","A","dsfaf123aasf42112dfa"))
#
# print(re.subn("\d+","A","dsfaf123aasf42112dfa"))
#
# # 规则,书写规则
# com = re.compile("\d+")
# str1 = "qfaqs234rer1344"
# print(com.findall(str1))
#
# com = re.compile("\d")
# print(com.findall(str1))
# # 迭代器
# ite = com.finditer(str1)
# # next(ite)
# print(ite)
# # ?: 去除优先级
# print(re.findall("www\.(baidu|163)\.com","www.163.com")) # 163
# print(re.findall("www\.(?:baidu|163)\.com","www.163.com")) # www.163.com
# print(re.search("abc|bcd", "abc"))  # search
# print(re.search("a(bc)|bcd", "abc").group())
# "\(9[^()]+\)" print(re.findall("(abc)+", "abcabcabc")) # 给整体添加匹配
print(re.findall("abc+", "abcccabcabcfadfabc")) # ?:去除优先级,给c添加重复匹配
 

最新文章

  1. ZOJ Problem Set - 1392 The Hardest Problem Ever
  2. Cloneable接口和Object的clone()方法
  3. 2.1 CMMI2级——7个PA简述
  4. libswscale图像格式转换与放大缩小
  5. Java基础知识强化之多线程笔记02:多线程之 面试题(常问)
  6. 多个DIV让float:left属性,最后一个DIV填满剩余的部分
  7. 根据input 标签取value属性的值
  8. Visual Studio 2013 新增web项目IIS Express的64位版   转载来源http://www.cnblogs.com/jianyus/p/3524335.html
  9. SQL游标使用及实例
  10. hdu5860 Death Sequence
  11. javaMail邮件发送功能(多收件人,多抄送人,多密送人,多附件)
  12. Win10 将slim加入PYTHONPYTH
  13. 解决linux下svn update 产生Node remains in conflict的问题
  14. plsql 工具怎样导出 oracle 表结构
  15. 设计模式【转自JackFrost的博客】
  16. mycat工作原理
  17. 渲染Web视图
  18. Hive 常用优化参数
  19. centos shell 编程-通过端口号kill对应的进程
  20. 批处理学习笔记3 - 变量声明和goto代替while循环

热门文章

  1. 交换机安全学习笔记 第四章 VLAN
  2. C++ day01 预备知识、C++综述、教材、推荐阅读。
  3. 洛谷 P2868 [USACO07DEC]观光奶牛Sightseeing Cows 题解
  4. x系统清理/tmp/文件夹的原理
  5. ArcGIS 在VS2010中 ESRI.ArcGIS.SOESupport.dll 无法正常加载的处理
  6. java8之stream和lambda表达式
  7. SAP发布wbservice,如果有权限管控的话,需要给这个webservice加权限
  8. 关于strcpy的安全函数的选择
  9. 关于 i++ 和 ++ i
  10. mydql 设置充许远程链接