(JAVA对进制的运算)A + B Again hdu2057 要复习
2024-10-17 23:49:35
（置顶，复习）A + B Again
链接：http://acm.hdu.edu.cn/showproblem.php?pid=2057
Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 35905 Accepted Submission(s):
14614
Problem Description
There must be many A + B problems in our HDOJ , now a
new one is coming.
Give you two hexadecimal integers , your task is to
calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it
!
new one is coming.
Give you two hexadecimal integers , your task is to
calculate the sum of them,and print it in hexadecimal too.
Easy ? AC it
!
Input
The input contains several test cases, please process
to the end of the file.
Each case consists of two hexadecimal integers A and
B in a line seperated by a blank.
The length of A and B is less than
15.
to the end of the file.
Each case consists of two hexadecimal integers A and
B in a line seperated by a blank.
The length of A and B is less than
15.
Output
For each test case,print the sum of A and B in
hexadecimal in one line.
hexadecimal in one line.
Sample Input
+A -A
+1A 12
1A -9
-1A -12
1A -AA
Sample Output
0
2C
11
-2C
-90
Author
linle
注：
此题就是利用Long.parseLong()和Long.toHexString（）的
replaceAll("\\+","")，是去除其中的‘+’，因为进制计算不支持带“+”的某一进制的数字字符串，‘-’可以，同时还需要判断正数负数，从而利用Long.toHexString（）。
Java代码：
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner inScanner = new Scanner(System.in);
while(inScanner.hasNext()) {
long l = Long.parseLong(inScanner.next().replaceAll("\\+", ""),16)
+ Long.parseLong(inScanner.next().replaceAll("\\+", ""),16);
if(l<0) {
System.out.println("-" + Long.toHexString(-l).toUpperCase());
}
else {
System.out.println(Long.toHexString(l).toUpperCase());
}
}
}
}
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