python spark 通过key来统计不同values个数

>>> rdd = sc.parallelize([("a", ""), ("b", 1), ("a", 1), ("a", 1)])

>>> rdd.distinct().countByKey().items()

[('a', 2), ('b', 1)]

OR:

from operator import add

rdd.distinct().map(lambda x: (x[0], 1)).reduceByKey(add)

rdd.distinct().keys().map(lambda x: (x, 1)).reduceByKey(add)

distinct(numPartitions=None)

Return a new RDD containing the distinct elements in this RDD.

>>> sorted(sc.parallelize([1, 1, 2, 3]).distinct().collect())

[1, 2, 3]

countByKey()

Count the number of elements for each key, and return the result to the master as a dictionary.

>>> rdd = sc.parallelize([("a", 1), ("b", 1), ("a", 1)])

>>> sorted(rdd.countByKey().items())

[('a', 2), ('b', 1)]

巴特西

python spark 通过key来统计不同values个数

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