In the modern time, Search engine came into the life of everybody like Google, Baidu, etc. 
Wiskey also wants to bring this feature to his image retrieval system. 
Every image have a long description, when users type some keywords to find the image, the system will match the keywords with description of image and show the image which the most keywords be matched. 
To simplify the problem, giving you a description of image, and some keywords, you should tell me how many keywords will be match. 

1

5

she

he

say

shr

her

yasherhs

3
AC自动机：利用ttie树节省空间，利用kmp相似的原理构建fail指针进行匹配

#include<iostream>

#include<cstdio>

#include<cmath>

#include<cstring>

#include<sstream>

#include<algorithm>

#include<queue>

#include<deque>

#include<iomanip>

#include<vector>

#include<cmath>

#include<map>

#include<stack>

#include<set>

#include<fstream>

#include<memory>

#include<list>

#include<string>

using namespace std;

typedef long long LL;

typedef unsigned long long ULL;

#define MAXN 26

#define L 31

#define INF 1000000009

#define eps 0.00000001

struct node

{

    node()

    {

        cnt = ;

        fail = NULL;

        for (int i = ; i < MAXN; i++)

            next[i] = NULL;

    }

    int cnt;

    struct node* next[MAXN];

    struct node* fail;

};

typedef struct node* Tree;

void insert(Tree T, const char* str)

{

    int p = ;

    Tree tmp = T;

    while (str[p] != '\0')

    {

        int k = str[p] - 'a';

        if (tmp->next[k] == NULL)

        {

            tmp->next[k] = new node();

        }

        tmp = tmp->next[k];

        p++;

    }

    tmp->cnt++;

}

void build_ac(Tree root)

{

    root->fail = NULL;

    queue<Tree> q;

    q.push(root);

    while (!q.empty())

    {

        Tree tmp = q.front();

        q.pop();

        Tree p = NULL;

        for (int i = ; i < MAXN; i++)

        {

            if (tmp->next[i] != NULL)

            {

                if (tmp == root)

                    tmp->next[i]->fail = root;

                else

                {

                    p = tmp->fail;

                    while (p != NULL)

                    {

                        if (p->next[i] != NULL)

                        {

                            tmp->next[i]->fail = p->next[i];

                            break;

                        }

                        p = p->fail;

                    }

                    if (p == NULL) tmp->next[i]->fail = root;

                }

                q.push(tmp->next[i]);

            }

        }

    }

}

int query(Tree root,const char* str)

{

    int i = ;

    int count = ;

    int l = strlen(str);

    Tree tmp = root;

    int index;

    while (str[i])

    {

        index = str[i] - 'a';

        while (tmp->next[index] == NULL && tmp != root)

            tmp = tmp->fail;

        tmp = tmp->next[index];

        if (tmp == NULL) tmp = root;

        Tree p = tmp;

        while (p != root)

        {

            count += p->cnt;

            p->cnt = ;

            p = p->fail;

        }

        i++;

    }

    return count;

}

void del(Tree root)

{

    for (int i = ; i < MAXN; i++)

        if (root->next[i] != NULL)

            del(root->next[i]);

    delete root;

}

char key[], s[];

int main()

{

    int T, n;

    scanf("%d", &T);

    while (T--)

    {

        scanf("%d", &n);

        Tree root = new node();

        root->cnt = ;

        root->fail = NULL;

        for (int i = ; i < MAXN; i++)

            root->next[i] = NULL;

        for (int i = ; i < n; i++)

        {

            scanf("%s", key);

            insert(root, key);

        }

        build_ac(root);

        scanf("%s", s);

        printf("%d\n", query(root, s));

        del(root);

    }

}