[leetcode-646-Maximum Length of Pair Chain]

You are given n pairs of numbers. In every pair, the first number is always smaller than the second number.

Now, we define a pair (c, d) can follow another pair (a, b) if and only if b < c. Chain of pairs can be formed in this fashion.

Given a set of pairs, find the length longest chain which can be formed. You needn't use up all the given pairs. You can select pairs in any order.

Example 1:

Input: [[1,2], [2,3], [3,4]]

Output: 2

Explanation: The longest chain is [1,2] -> [3,4]

Note:

The number of given pairs will be in the range [1, 1000].

思路：
动态规划。递推公式是 dp[i] = max(dp[i],dp[j]+1);其中0=<j<i;

int findLongestChain(vector<vector<int>>& pairs)

    {

        sort(pairs.begin(), pairs.end(), [](const vector<int>&a, const vector<int>&b){return a[] < b[]; });

        vector<int> dp(pairs.size(), );

        for (int i = ; i < pairs.size(); i++)

        {

            for (int j = ; j<i;j++)

            {

                if (pairs[i][]>pairs[j][])

                {

                    dp[i] = max(dp[i],dp[j]+);

                }

            }

        }

        return *max_element(dp.begin(), dp.end());

    }

巴特西

[leetcode-646-Maximum Length of Pair Chain]

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