<已解决>使用selector设置Button按下松开的样式以及 <item> tag requires a 'drawable' attribute or child tag defining a drawable 报错

<?xml version="1.0" encoding="utf-8"?>

<selector xmlns:android="http://schemas.android.com/apk/res/android">

    <item android:color="@color/flatui_clouds" android:state_pressed="true" />

    <item android:color="@color/flatui_peter_river" />

</selector>

在Drawable/中定义了一个selector来进行按钮按下和松开的背景色变换,可是在运行时报错 <item> tag requires a 'drawable' attribute or child tag defining a drawable

解决方案:

把 android:background = "@drawable/button_anim" 改为 android:drawable= "@drawable/button_anim"

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更新: 无卵用

17:51更新

Why not simply use "drawable="@color/your_color" directly in your selector items instead? You don't need to define any shapes or any other files whatsoever, just have your color definitions in values/colors.xml (it's always good not to hardcode colors). – javaxian Apr 13 '14 at 13:37

<?xml version="1.0" encoding="utf-8"?>

<selector xmlns:android="http://schemas.android.com/apk/res/android">

    <item android:drawable="@color/flatui_midnight_blue" android:state_pressed="true" />

    <item android:drawable="@color/flatui_concrete" />

</selector>

巴特西

<已解决>使用selector设置Button按下松开的样式以及 <item> tag requires a 'drawable' attribute or child tag defining a drawable 报错

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