2017杭电多校第六场1011Classes
传送门
Classes
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 0 Accepted Submission(s): 0
Now the school wants to count the number of students who enrolled in at least one course in each class and records the maximum number of students.
Each class uploaded 7 data, the number of students enrolled in course A in the class, the number of students enrolled in course B, the number of students enrolled in course C, the number of students enrolled in course AB, the number of students enrolled in
course BC, the number of students enrolled in course AC, the number of students enrolled in course ABC. The school can calculate the number of students in this class based on these 7 data.
However, due to statistical errors, some data are wrong and these data should be ignored.
Smart you must know how to write a program to find the maximum number of students.
Each case begins with one line with one integer N, indicates the number of class.
Then N lines follow, each line contains 7 data: a, b, c, d, e, f, g, indicates the number of students enrolled in A, B, C, AB, BC, AC, ABC in this class.
It's guaranteed that at least one data is right in each test case.
Limits
T≤100
1≤N≤100
0≤a,b,c,d,e,f,g≤100
2
4 5 4 4 3 2 2
5 3 1 2 0 0 0
2
0 4 10 2 3 4 9
6 12 6 3 5 3 2
15
In the second test case, the data uploaded by Class 1 is wrong.
Because we can't find a solution which satisfies the limitation.
As for Class 2, we can calculate the number of students who only enrolled in course A is 2,
the number of students who only enrolled in course B is 6, and nobody enrolled in course C,
the number of students who only enrolled in courses A and B is 1,
the number of students who only enrolled in courses B and C is 3,
the number of students who only enrolled in courses A and C is 1,
the number of students who enrolled in all courses is 2,
so the total number in Class 2 is 2 + 6 + 0 + 1 + 3 + 1 + 2 = 15.
Statistic | Submit | Clarifications | Back
代码如下
#include <iostream>
#include <string>
#include<algorithm>
#include<cstring>
#include<cstdio>
using namespace std;
#define ll long long
int main()
{
int a, b, c, ab, bc, ac, abc;
int t,n,ans=0;
cin >> t;
while (t--) {
ans = 0;
cin >> n;
for (int i = 0; i < n;++i) {
int cnt = 0;
cin >> a >> b >> c >> ab >> bc >> ac >> abc;
ac =ac-abc;
bc =bc-abc;
ab =ab-abc;
if (ab < 0 || bc < 0 || ac < 0)
continue;
a = a - ab - ac - abc;
b = b - ab - bc - abc;
c = c - ac - bc - abc;
if (a < 0 || b < 0 || c < 0)
continue;
cnt += a + b + c + ab + ac + bc + abc;
ans = max(ans, cnt);
}
cout << ans << endl;
}
return 0;
}
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