class Solution {

public:

    ListNode* Merge(ListNode* pHead1, ListNode* pHead2)

    {

        ListNode* Node = NULL;

        if(pHead1 != NULL && pHead2 != NULL){

            if(pHead1->val < pHead2->val){

                Node = pHead1;

                Node->next = Merge(pHead1->next,pHead2);

            }

            else{

                Node = pHead2;

                Node->next = Merge(pHead1,pHead2->next);

            }

        }

        if(pHead1 != NULL)

            Node = pHead1;

        if(pHead2 != NULL)

            Node = pHead2;

        return Node;

    }

};

测试用例:
{1,3,5},{2,4,6}

对应输出应该为:

{1,2,3,4,5,6}

你的输出为:

{2,4,6}