笨办法学Python记录--习题38-40,复习前面,运用list操作函数
#习题38 区分列表和字符串,用到了split(字符串专用函数),join、append、pop(这些是list操作函数)
ten_things = "Apples Oranges Crows Telephone Liht Sugar" print "Wait there is not 10 things in that list, let's fix that." stuff=ten_things.split(' ') more_stuff = ["Day","Night","Song","Frisbee","Corn","Banana","Girl","Boy"] while len(stuff)!=10:
next_one = more_stuff.pop()
print "Adding:",next_one
stuff.append(next_one)
print "There's %d items now." % len(stuff) print "There we go:",stuff
print "Let's do some things with stuff." print "stuff[1]"
print stuff[1] print "stuff[-1]"
print stuff[-1] print "stuff.pop()"
print stuff.pop() print "' '.join(stuff)"
print ' '.join(stuff) print "'#'.join(stuff[3:5]"
print '#'.join(stuff[3:5] )
结果:
#习题38 区分列表和字符串,同时学者使用split函数
ten_things = "Apples Oranges Crows Telephone Liht Sugar"
print "Wait there is not 10 things in that list, let's fix that."
stuff=ten_things.split(' ')
more_stuff = ["Day","Night","Song","Frisbee","Corn","Banana","Girl","Boy"]
while len(stuff)!=10:
next_one = more_stuff.pop()
print "Adding:",next_one
stuff.append(next_one)
print "There's %d items now." % len(stuff)
print "There we go:",stuff
print "Let's do some things with stuff."
print "stuff[1]"
print stuff[1]
print "stuff[-1]"
print stuff[-1]
print "stuff.pop()"
print stuff.pop()
print "' '.join(stuff)"
print ' '.join(stuff)
print "'#'.join(stuff[3:5]"
print '#'.join(stuff[3:5]
)
个人觉得这么使用字典很帅很帅!!
cities = {'CA':'San Francisco','MI':'Detroit','FL':'Jacksonville'}
cities['NY']='New York'
cities['OR']='Portland' def find_city(themap,state):
if state in themap:
return themap[state]
else:
return "Not found." cities['_find'] = find_city while True:
print "State?(ENTER to quit)",
state = raw_input("> ") if not state:break
city_found = cities['_find'](cities,state)
print city_found
关于字典:字典出现在当索引不好用的时候--字典中的值并没有特殊的顺序,但是都存储在一个特定的键(key)里。key可以是数字、字符串甚至元组。
字典应用:1. 数字电话/地址簿;2. 存储文件修改次数,用文件名作为键;3. 表征游戏键盘的状态,每个键都是由坐标值组成的元组;
dict函数的使用:
>>>d=dict(name='GG', age=32)
>>>d
{'age':32,'name':'GG'}
or
>>>a=[('name','GG'),('age',42)]
>>>d=dict(a)
简单数据库实现:
people = {'Alice':{'phone':'','addr':'Foo drive 23'},'Beth':{'phone':'','addr':'Bar steet 42'},'Cecil':{'phone':'','addr':'Baz avenue 90'}}
labels = {'phone':'phone number','addr':'address'}
name = raw_input('Name: ')
request=raw_input('phone number(p) or address(a)?')
if request=='p':
key = 'phone'
if request == 'a':
key = 'addr'
if name in people:
print "%s's %s is %s." % (name,labels[key],people[name][key])
深拷贝,浅拷贝
待续
最新文章
- centos6环境下搭建irc服务器
- [转]CIDR简介
- 表单提交set集合问题
- codeforces B. Permutation 解题报告
- SpringMvc中的反射
- C++中求两个正整数的最大公约数和最小公倍数
- 劳动节BT5 aircrack-ng战记
- android学习日记18--Adapter简介
- 【HDOJ】4278 Faulty Odomete
- 程序猿都是project师吗?
- 【搜索引擎Jediael开发笔记2】使用HttpClient下载网页至本地文件
- Unity Container
- Ubuntu上64位adv无法创建问题
- dict的操作和三级菜单
- POJ - 3984 迷宫问题 bfs解法
- 1259 整数划分 V2
- 【UML】Java代码与UML模型相互转换方法
- (转)Eclipse配置GitHub代码库(以Windows7为例)
- 《剑指offer》第六十八题(树中两个结点的最低公共祖先)
- [剑指Offer]22-链表中倒数第k个结点
热门文章
- JindoFS解析 - 云上大数据高性能数据湖存储方案
- AndroidManifest.xml配置文件详解(转)
- windows下tomcat7+nginx1.8负载均衡
- 原来... 用debug如何查看当前标志寄存器的标志位值?
- 2、jQuery操作Dom(过滤器与选择器)
- 畜禽免疫系统使用LODOP打印
- testNG官方文档翻译-5 测试方法,测试类和测试组
- Eureka 系列(06)消息广播(下):TaskDispacher 之 Acceptor - Worker 模式
- 利用os和pandas来合并当前目录下所有excel文件
- 10-vim-选中命令-01-三种选择文本的方式