set()运算

1 计算两个list的关系时,可转化为set进行运算.

参考：https://www.runoob.com/python3/python3-set.html

a =[1,4,3,5,6,6,7,7,7]

b =[2,2,3,3,1,1,22]

a = set(a)

b = set(b)

# a与b的差集

print(a - b)

# a与b的交集

print(a & b)

print(a.intersection(b))

# a与b的并集

print(a | b)

print(a.union(b))

# 不同时包含于a和b的元素,类似于symmetric_difference_update函数

print(a ^ b)

# {4, 5, 6, 7}

# {1, 3}

# {1, 3}

# {1, 2, 3, 4, 5, 6, 7, 22}

# {1, 2, 3, 4, 5, 6, 7, 22}

# {2, 4, 5, 6, 7, 22}

对于list中是字符串的情况同样可以使用

a = ['a','b','c','d']

b = ['a','b','p','q']

print( set(a) & set(b))

# {'a', 'b'}

巴特西

set()运算

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