HDU2899 Strange fuction 【二分】
2024-09-07 13:33:46
Strange fuction
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 2982 Accepted Submission(s): 2202
Problem Description
Now, here is a fuction:
F(x) = 6 * x^7+8*x^6+7*x^3+5*x^2-y*x (0 <= x <=100)
Can you find the minimum value when x is between 0 and 100.
F(x) = 6 * x^7+8*x^6+7*x^3+5*x^2-y*x (0 <= x <=100)
Can you find the minimum value when x is between 0 and 100.
Input
The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has only one real numbers Y.(0 < Y <1e10)
Output
Just the minimum value (accurate up to 4 decimal places),when x is between 0 and 100.
Sample Input
2
100
200
Sample Output
-74.4291
-178.8534
#include <stdio.h>
#include <math.h>
double y, ans; double f(double x){
return 6 * pow(x, 7) + 8 * pow(x, 6) +
7 * pow(x, 3) + 5 * x * x - y * x;
} double ff(double x){ //求导
return 42 * pow(x, 6) + 48 * pow(x, 5)
+ 21 * x * x + 10 * x - y;
} int main(){
int n;
scanf("%d", &n);
while(n--){
scanf("%lf", &y);
if(ff(0) >= 0) ans = f(0);
else if(ff(100) <= 0) ans = f(100);
else{
double left = 0, right = 100, mid;
while(left + 1e-8 < right){
mid = (left + right) / 2;
if(ff(mid) > 0) right = mid;
else if(ff(mid) < 0) left = mid;
else break;
}
ans = f(mid);
}
printf("%.4lf\n", ans);
}
return 0;
}
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