URAL 2040 Palindromes and Super Abilities 2

Palindromes and Super Abilities 2
Time Limit: 500MS Memory Limit: 102400KB 64bit IO Format: %I64d & %I64u

Description

Dima adds letters s₁, …, s_n one by one to the end of a word. After each letter, he asks Misha to tell him how many new palindrome substrings appeared when he added that letter. Two substrings are considered distinct if they are different as strings. Which n numbers will be said by Misha if it is known that he is never wrong?

Input

The input contains a string s₁ … s_n consisting of letters ‘a’ and ‘b’ (1 ≤ n ≤ 5 000 000).

Output

Print n numbers without spaces: i-th number must be the number of palindrome substrings of the prefix s₁ … s_i minus the number of palindrome substrings of the prefix s₁ … s_i−1. The first number in the output should be one.

Sample Input

abbbba

Sample Output

111111

Notes

We guarantee that jury has C++ solution which fits Time Limit at least two times. We do not guarantee that solution on other languages exists (even Java).

Source

Problem Author: Mikhail Rubinchik (prepared by Kirill Borozdin)

解题：PalindromicTree

 #include <bits/stdc++.h>

 using namespace std;

 const int maxn = ;

 struct PalindromicTree{

     struct node{

         int son[],f,len;

         void init(int len){

             memset(son,,sizeof son);

             this->len = len;

         }

     }e[maxn];

     int tot,last,n;

     char s[maxn];

     int newnode(int len = ){

         e[tot].init(len);

         return tot++;

     }

     int getFail(int x){

         while(s[n - e[x].len - ] != s[n]) x = e[x].f;

         return x;

     }

     void init(){

         last = tot = n = ;

         newnode();

         newnode(-);

         e[].f = ;

         s[n] = -;

     }

     bool extend(int c){

         s[++n] = c;

         int cur = getFail(last);

         bool isExtend = e[cur].son[c] == ;

         if(!e[cur].son[c]){

             int newson = newnode(e[cur].len + );

             e[newson].f = e[getFail(e[cur].f)].son[c];

             e[cur].son[c] = newson;

         }

         last = e[cur].son[c];

         return isExtend;

     }

 }pt;

 char str[maxn];

 int main(){

     while(gets(str)){

         pt.init();

         for(int i = ; str[i]; ++i){

             if(pt.extend(str[i] - 'a')) putchar('');

             else putchar('');

         }

         putchar('\n');

     }

     return ;

 }

巴特西

URAL 2040 Palindromes and Super Abilities 2

Notes

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