#!/usr/bin/env/python

# -*-coding:utf-8-*-

# authour:xiapmin_pei

import copy

#定义一个元组，元组里面有一个列表，可以理解成内部

atuple=(1,2,3,[4,5])

#将元组赋值给b

b = atuple

#浅拷贝

c = copy.copy(atuple)

#深拷贝

d = copy.deepcopy(atuple)

#打印每个对象的值

print "b is {0},c is {1},d is {2}".format(b,c,d)

#改变atuple里面内嵌的列表，给列表增加一个6

atuple[3].append(6)

print "b is {0},c is {1},d is {2}".format(b,c,d)

结果：可以看出来，将atuple赋值给b，b和atuple始终是一致的
　　　浅拷贝外面一层不会变，但是嵌套的列表会改变
　　  深拷贝只和atuple的原始一样，不会随着atuple的改变而改变

b is (1, 2, 3, [4, 5]), c is (1, 2, 3, [4, 5]), d is (1, 2, 3, [4, 5])
b is (1, 2, 3, [4, 5, 6]), c is (1, 2, 3, [4, 5, 6]), d is (1, 2, 3, [4, 5])

#!/usr/bin/env/python

# -*-coding:utf-8-*-

# authour:xiapmin_pei

import copy

alist = [1,2,3,[4,5]]

b = alist

c = copy.copy(alist)

d = copy.deepcopy(alist)

print "alist是{0},b是{1},  c是{2},  d是{3}".format(alist,b,c,d)

alist[3].append(6)

print "alist是{0},b是{1},  c是{2},  d是{3}".format(alist,b,c,d)

alist.append(7)

print "alist是{0},b是{1},  c是{2},  d是{3}".format(alist,b,c,d)

结果：可以看出来，将alist赋值给b，b无论怎么变化，都是和alist是一样的
　　  浅拷贝copy只拷贝第一层，第一层不改变，但是嵌套的列表随着alist的改变而改变
　　  深拷贝deepcopy只和原先的alist是一致的，无论alist怎么改变，deepcopy只拷贝一次原先的。

alist是[1, 2, 3, [4, 5]],b是[1, 2, 3, [4, 5]], c是[1, 2, 3, [4, 5]], d是[1, 2, 3, [4, 5]]
alist是[1, 2, 3, [4, 5, 6]],b是[1, 2, 3, [4, 5, 6]], c是[1, 2, 3, [4, 5, 6]], d是[1, 2, 3, [4, 5]]
alist是[1, 2, 3, [4, 5, 6], 7],b是[1, 2, 3, [4, 5, 6], 7], c是[1, 2, 3, [4, 5, 6]], d是[1, 2, 3, [4, 5]]