描述

When Teddy was a child , he was always thinking about some simple math problems ,such as “What it’s 1 cup of water plus 1 pile of dough ..” , “100 yuan buy 100 pig” .etc..

One day Teddy met a old man in his dream , in that dream the man whose name was“RuLai” gave Teddy a problem :

Given an N , can you calculate how many ways to write N as i * j + i + j (0 < i <= j) ?

Teddy found the answer when N was less than 10…but if N get bigger , he found it was too difficult for him to solve.
Well , you clever ACMers ,could you help little Teddy to solve this problem and let him have a good dream ?

输入

The first line contain a T(T <= 2000) . followed by T lines ,each line contain an integer N (0<=N <= 10^11).

输出

For each case, output the number of ways in one line

样例输入

2

1

3

样例输出

0

1

#include <iostream>

#include <vector>

#include <cmath>

using namespace std;

int main(){

    int T;

    cin >> T;

    for(int  icase  =  ; icase < T; icase ++){

        int n;

        cin >> n;

        n++;

        int res = ;

        for(int i = ; i <= (int)sqrt(n); ++ i){

            if(n%i == ) res ++ ;

        }

        cout<< res<<endl;

    }

}

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