Manthan, Codefest 16(B--A Trivial Problem)

B. A Trivial Problem

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

Mr. Santa asks all the great programmers of the world to solve a trivial problem. He gives them an integer m and asks for the number of positive integers n, such that the factorial ofn ends with exactly m zeroes. Are you among those great programmers who can solve this problem?

Input

The only line of input contains an integer m (1 ≤ m ≤ 100 000) — the required number of trailing zeroes in factorial.

Output

First print k — the number of values of n such that the factorial of n ends with m zeroes. Then print these k integers in increasing order.

Examples

input

output

5
5 6 7 8 9

input

output

Note

The factorial of n is equal to the product of all integers from 1 to n inclusive, that isn! = 1·2·3·...·n.

In the first sample, 5! = 120, 6! = 720, 7! = 5040, 8! = 40320 and 9! = 362880.

题目纠结时间有点长。。

package ManthanCodefest16;

import java.io.InputStreamReader;

import java.math.BigInteger;

import java.util.Scanner;

/**

 * Created by lenovo on 2016-03-02.

 */

public class B {

    public static void main(String[] args){

        Scanner scanner = new Scanner(new InputStreamReader(System.in));

        /*

        * 这道题目是数一个数中能被 5 整除的次数，然后每次都能找到这个序列末尾的数，而且除了第一组

        * 其他的都是5个数字一组。恩，就这样

        * */

        int m;

        int[] arr = new int[100000 + 100];

        arr[0] = 4;

        arr[1] = 9;

        int num = 1;

        for(int i = 2; i < arr.length;){

            arr[i] = arr[i-num] + 5;

            num = num(arr[i]+1);

            i += num;

        }

        while(scanner.hasNext()){

            m = scanner.nextInt();

            if(arr[m] == 0){

                System.out.println(0);

            } else {

                if(arr[m] == 4){

                    System.out.println(4);

                    for(int i = 1; i <= arr[m]; ++i){

                        System.out.print(i+" ");

                    }

                } else {

                    System.out.println(5);

                    for(int i = arr[m]-5; i <= arr[m]; ++i){

                        System.out.println(i+" ");

                    }

                }

            }

        }

    }

    public static int num(int n){

        int cnt = 0;

        while(n % 5 == 0 && n != 0){

            n /= 5;

            cnt++;

        }

        return cnt;

    };

}

巴特西

Manthan, Codefest 16(B--A Trivial Problem)

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