list_1 = [1,2,3,4,23,4,2]

print(list_1,type(list_1))

list_1 = set(list_1)

print(list_1,type(list_1))

list_2 = set([2,4,6,8,10])

print(list_2,type(list_2))

#运行结果

[1, 2, 3, 4, 23, 4, 2] <class 'list'>

{1, 2, 3, 4, 23} <class 'set'>

{8, 2, 10, 4, 6} <class 'set'>

############################# 集合的关系测试 part ###################################

#交集

print(list_1.intersection(list_2))

#对称差集  除去两个集合的交集的那部分

print(list_1.symmetric_difference(list_2))

#并集

print(list_1.union(list_2))

#差集

# is in list_1 , but not in list_2

print(list_1.difference(list_2))

# is in list_2, but not in list_1

print(list_2.difference(list_1))

#子集

list_3 = set([6,8,10])

print(list_3.issubset(list_2))

#父集

print(list_2.issuperset(list_3))

#""" Return True if two sets have a null intersection. """

print(list_1.isdisjoint(list_3))

print(list_1.isdisjoint(list_2))

'''

#交集

print("交集->", list_1 & list_2)

#union

print("并集->", list_1 | list_2)

# difference

print("difference-->",list_1 - list_2)  # is in list_1 but not in list_2

#对称差集

print("对称差集-->", list_1 ^ list_2)

list_1 = (1,3,5,7)

list_2 = ([1,3,5,7])

list_3 = set([1,3,5,7])

print(list_1,type(list_1))

print(list_2,type(list_2))

print(list_3,type(list_3))

#1.添加一项 add, 添加多项update

list_3.add(9)

print("test1--",list_3)

list_3.update([11,13])

print("test2--",list_3)

# 2.移走一项

list_3.remove(11)

print("test3--",list_3)

#.3 长度

print("test4--",len(list_3))

# 4.在不在里面

print("test5---", 6 in list_3, 3 in list_3, 11 not in list_3)

# 5.删除任意的set element ，并返回

print(list_3.pop())

list_3.discard() # Remove an element from a set if it is a member.If the element is not a member, do nothing.

list_3.remove() #Remove an element from a set; it must be a member. If the element is not a member, raise a KeyError