ACM Color the fence

Color the fence

时间限制：1000 ms | 内存限制：65535 KB

难度：2

描述: Tom has fallen in love with Mary. Now Tom wants to show his love and write a number on the fence opposite to

Mary’s house. Tom thinks that the larger the numbers is, the more chance to win Mary’s heart he has.

Unfortunately, Tom could only get V liters paint. He did the math and concluded that digit i requires ai liters paint.

Besides,Tom heard that Mary doesn’t like zero.That’s why Tom won’t use them in his number.

Help Tom find the maximum number he can write on the fence.

输入

There are multiple test cases.
Each case the first line contains a nonnegative integer V(0≤V≤10^6).
The second line contains nine positive integers a1,a2,……，a9(1≤ai≤10^5).

输出

Printf the maximum number Tom can write on the fence. If he has too little paint for any digit, print -1.

样例输入

5

5 4 3 2 1 2 3 4 5

2

9 11 1 12 5 8 9 10 6

样例输出

55555

33
本题题意是给V升的油漆，以及1-9每个数字需要的油漆，问用这些油漆能刷出的最大的数字？
如给得第一个测试用例，有5升油漆，数字5需要1升油漆，故把数字5刷5次得到的数字最大
但存在这样的测试用例
9
5 4 2 3 5 4 6 4 5
则全用来刷数字3的话，为3333，还剩1升油漆
如果刷3个数字2，还剩3升用来刷数字4，则结果为4333，比全用来刷数字2大
同时还存在一种测试用例
8
5 4 3 2 5 4 6 1 1
有油漆相同的情况，应该选择数字最大的
本题还未考虑下面这种情况，参考codeforce给出的测试用例才知道

898207

99745 99746 99748 99752 99760 99776 99808 99872 100000
结果为987654321

#include <iostream>

#include <vector>

#include <algorithm>

using namespace std;

int main(){

    int v;

    while(cin >> v){

        vector<int> num(,);

        int minIndex = ;

        for(int i =  ; i < ; ++ i){

            cin >> num[i];

            if(num[minIndex]>=num[i]) minIndex = i;

        }

        if(v < num[minIndex]) cout<<-<<endl;

        else if(v%num[minIndex] == ) cout<<string(v/num[minIndex],''+minIndex)<<endl;

        else{

            int cnt = v/num[minIndex], remain = v%num[minIndex];

            for(int i =  ; i < cnt; ++ i){

                for(int j =  ; j > ; -- j){

                    if(j <= minIndex){

                        cout<<minIndex;

                        break;

                    }

                    if(remain-(num[j]-num[minIndex]) >= ){

                        remain -=(num[j]-num[minIndex]);

                        cout<<j;

                        break;

                    }

                }

            }

            cout<<endl;

        }

    }

}

巴特西

ACM Color the fence

Color the fence

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